Find the number which will divide 398 and 436, leaving remainders 11 and 15 respectively.
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The number 398, 436 and 542 which when divides by a positive integers leaves remainder as 7, 11, and 15 respectively . → Clearly, the required number divides ( 398 - 7 ) = 391 , ( 436 - 11 ) = 425, and ( 542 - 15 ) = 527 exactly
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