Math, asked by aasthaporwal47, 7 months ago

Find the number which will divide 398 and 436, leaving remainders 11 and 15 respectively.

PLEASE ANSWER MY QUESTION FAST
IT'S SO MUCH URGENT...​

Answers

Answered by mathurmadhulika
1

if it's smallest no. follow these rules

  • add 398 + 11 and 436 + 15 respectively
  • now find the HCF of 398 + 11 and 436 + 15
  • done !!

Answered by muhammadjawad309
1

Answer:

17

Step-by-step explanation:

17 is the digit which will divide 398 and the remainder will be 11 and when we divide 436 with 17 then well get 15 remainders,

that's the required result.

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