Find the number which will divide 398and 436, leaving remainder 11 and 15 respectvily
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Answer:
The number 398, 436 and 542 which when divides by a positive integers leaves remainder as 7, 11, and 15 respectively . → Clearly, the required number divides ( 398 - 7 ) = 391 , ( 436 - 11 ) = 425, and ( 542 - 15 ) = 527 exactly
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Step-by-step explanation:
398 -11 =391
436 - 15 = 425.
The required number = HCF( 391,425) = 17.
17×23 = 391
17×25 = 425.
THEREFORE THE ANSWER IS 17.
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