Question

find the number whose 10th part increased by 10 is equal to its eighth part diminished by 10
​

Answer 1

Answer:

Let the no. xATQ,x/10+10=x/8-10(x+100)/10=(x-80)/88(x+100)=10(x-80)8x+800=10x-800-2x =-1600x=800it is the answer

HOPE IT HELPS

MARK ME AS BRAINLIEST

Answer 2

Answer:

The correct answer is x=800.

Step-by-step explanation:

The problem can be written as following

x/10 + 10 = x/8 - 10

20=x/40

x=800

PLEASE MARK AS BRAINLIEST ANSWER DON'T FORGET TO PRESS ON THANKS IF YOU FIND IT HELPFUL