Find the number whose 15% is 240.
दिये गये चित्र में OA और OB विपरीत किरणें हैं और ZAOC + ZBOD = 90° हो तो ZCOL
का मान ज्ञात कीजिए।
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1 the given figure OA and OB are opposite rays and ZAOC + ZBOD= 90° th
nd the value of ZCOD.
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Given : OA and OB are opposite rays and ∠AOC + ∠BOD= 90°
To find : ∠COD
Solution:
Let say Number = N
whose 15 % is 240
=> (15/100)N = 240
=> N = 1600
15 % of 1600 is 240
OA & OB are opposite rays
hence AB is straight line
∠AOC + ∠COD + ∠BOD = 180°
=> ∠AOC + ∠BOD + ∠COD = 180°
∠AOC + ∠BOD = 90° given
=> 90° + ∠COD = 180°
=> ∠COD = 90°
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