Question

Find the number whose 15% is 240.दिये गये चित्र में OA और OB विपरीत किरणें हैं और ZAOC + ZBOD = 90° हो तो ZCOLका मान ज्ञात कीजिए।DR>BOA1 the given figure OA and OB are opposite rays and ZAOC + ZBOD= 90° thnd the value of ZCOD.DR•C​

Answer 1

Given : OA and OB are opposite rays and ∠AOC + ∠BOD= 90°  

To find :  ∠COD

Solution:

Let say Number = N  

whose 15 % is 240

=> (15/100)N = 240

=>  N = 1600

15 % of 1600 is 240

OA & OB are opposite rays

hence AB is straight line

∠AOC  +  ∠COD + ∠BOD = 180°

=> ∠AOC  + ∠BOD +  ∠COD  = 180°

∠AOC  + ∠BOD   = 90°  given

=> 90°  +  ∠COD  = 180°

=> ∠COD  = 90°  

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