find the number whose 5th part exceeds its 9th part by 4
Answers
Answered by
12
Solution :
Let the number = x
5th part of the number = x/5
9th part of the number = x/9
According to the problem given,
x/5 - x/9 = 4
=> ( 9x - 5x )/45 = 4
=> 4x/45 = 4
=> x = ( 45 × 4 )/4
=> x = 45
Therefore ,
Required number (x) = 45
••••
agentm1958:
Thank u very much
Answered by
0
Answer:
Step-by-step explanation:
x/5 = 4 + x/9
9x = 180 + 5x
4x = 180
x = 45.
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