Question

find the number whose 5th part exceeds its 9th part by 4​

Answer 1

Solution :

Let the number = x

5th part of the number = x/5

9th part of the number = x/9

According to the problem given,

x/5 - x/9 = 4

=> ( 9x - 5x )/45 = 4

=> 4x/45 = 4

=> x = ( 45 × 4 )/4

=> x = 45

Therefore ,

Required number (x) = 45

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Answer 2

Answer:

Step-by-step explanation:

x/5 = 4 + x/9

9x = 180 + 5x

4x = 180

x = 45.