Question

find the number whose 5th part increased by 5 in equal to 4th part dimenised by 5.

Answer 1

Let the Number be x,


$\frac{x}{5} + 5 = \frac{x}{4} - 5\\ \\ \\ \frac{x}{5} - \frac{x}{4} = - 5 - 5 \\ \\ \\ \frac{4x - 5x }{20} = - 10 \\ \\ - x = - 10 \times 20 \\ \\ \\ - x = - 200 \\ \\ x = 200$


Required number is 200




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Answer 2

Heya !!!


Let number be X.



5th part of X = 1/5 × ( X ) = X/5



And,


Fourth part of X = 1/4 × (X) = X/4



According to question,



X/5 + 5 = X/4 -5



X + 25/5 = X - 20/4


4 ( X + 25) = 5 ( X - 20)


4X + 100 = 5X - 100



5X - 4X = 100+100


X = 200


Hence,


Required Number is 200.



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