Question

find the number whose double exceeds its half by 9

Answer 1

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Answer 2

Number is 6 whose double exceeds its half by 9

Given:

A number whose double exceeds its half by 9

To Find:

The number

Solution:

Step 1:

Assume that number is x

Step 2:

Find Double of the number

2x

Step 3:

Find half of the number

x/2

Step 4:

double exceeds half by 9 hence

2x = x/2 + 9

Step 5:

Solve for x

4x = x + 18

=> 3x = 18

=> x = 6

Hence number is 6 whose double exceeds its half by 9