Question

Find the number whose double is 45 greater than it's half.​

Answer 1

Answer:

30.

step by step explaination:

Let x

be the required number.

Now the double of a number will be 2x

and the half of a number will be x2

.

Since we are given that a number whose double is 45 greater than its half, so mathematically we can write

2x=x2+45

By rewriting the equation, we get

⇒2x−x2=45

Taking LCM on LHS, we get

⇒2x×22−x2=45

By simplifying the equation, we get

⇒4x2−x2=45

⇒4x−x2=45

Subtracting the terms in the denominator, we get

⇒3x2=45

Multiplying both sides by 2, we get

⇒3x=45×2

⇒3x=90

Dividing both sides by 3, we get

⇒x=903

⇒x=30

Therefore, the number whose double is 45 greater than its half is 30

.

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