Math, asked by keshew30, 11 months ago

find the number whose fifth part exceeds its ninth part by 4​

Answers

Answered by speedonly58
1

Answer:Let the number be x

x/5-x/9=4

4x/45=4

x= 180/4

X=45

Answered by mysticd
0

Answer:

Required number (x)=45

Explanation:

Let the number = x

fifth part of x = x/5

ninth part of x = x/9

According to the problem given,

x/5-x/9 = 4

=> (9x-5x)/45 = 4

=> 4x/45 = 4

=> x = (4×45)/4

=> x = 45

Therefore,

Required number = x = 45

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