find the number whose fifth part exceeds its ninth part by 4
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Answered by
1
Answer:Let the number be x
x/5-x/9=4
4x/45=4
x= 180/4
X=45
Answered by
0
Answer:
Required number (x)=45
Explanation:
Let the number = x
fifth part of x = x/5
ninth part of x = x/9
According to the problem given,
x/5-x/9 = 4
=> (9x-5x)/45 = 4
=> 4x/45 = 4
=> x = (4×45)/4
=> x = 45
Therefore,
Required number = x = 45
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