Question

find the number whose fifth -part increase by 5 is equal to its fourth part diminished by 5.​

Answer 1

Answer:

Let the number be x.

According to the question we can write as (1/5)x+5=(1/4)x−5

On rearranging

(1/5)x−(1/4)x=−5−5

(1/5)x−(1/4)x=−10

Now taking the L.C.M we get

(4x−5x)/20=−10

Again by transposing

X=200

Answer 2

Step-by-step explanation:

Let the number be x.

According to the question we can write as (1/5)x+5=(1/4)x−5

On rearranging

(1/5)x−(1/4)x=−5−5

(1/5)x−(1/4)x=−10

Now taking the L.C.M we get

(4x−5x)/20=−10

Again by transposingLet the number be x.

According to the question we can write as (1/5)x+5=(1/4)x−5

On rearranging

(1/5)x−(1/4)x=−5−5

(1/5)x−(1/4)x=−10

Now taking the L.C.M we get

(4x−5x)/20=−10

Again by transposing

X=200

Hope its help..