find the number whose fifth part increased by 5 is equal to its fourth part diminished by 5.
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Answer:
x=200
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Answered by
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Finding the number
Answer: Required number is 200.
Explanation:
Given that for a number if a fifth part is increased by 5 , is equal to fourth part diminished by 5
let number by x
fifth part of the number = x/5
fifth part increased by 5 = (x/5) + 5 ---------eq(1)
fourth part of the number = x/4
fourth part diminished by 5 = (x/4) - 5 ---------eq(2)
As fifth part increased by 5 = fourth part diminished by 5 , equating eq(1) and eq(2) we get
(x/5) + 5 = (x/4) - 5
=> (x/5) - (x/4) = -5 - 5
=> ( 4x - 5x )/20 = -10
=> -x/20 = -10
=> -x = -10 × 20
=> x = -200
=> x = 200
Hence required number is 200.
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