find the number whose fifth part increased by 5 is equal to its fourth part dimensional by 5
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Answer :
- The number is 200.
Given :
- A number whose fifth part increased by 5 is equal to its fourth part dimensional by 5
To find :
- The number
Solution :
- Let the number be x
According to question :
The number whose fifth part increased by 5 is equal to its fourth part dimensional by 5 so,
➟ x/5 + 5 = x/4 - 5
➟ x/5 - x/4 = -5 - 5
➟ 4x - 5x / 20 = 10
Cross multiplying we get
➟ -x = - 10 × 200
➟ -x = -200
➟ x = 200
Hence , The number is 200.
Verification :
➟ x/5 + 5 = x/4 - 5
➟ 200/5 + 5 = 200/4 - 5
➟ 40 + 5 = 50 - 5
➟ 45 = 45
Hence , Verified
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