Question

find the number whose fifth part increased by 5 is equal ton its fourth part diminished by 5

Answer 1

Answer:

200

Step-by-step explanation:

Let number be 'X'

Let number be 'X'> It's fifth part = X/5

Let number be 'X'> It's fifth part = X/5> Fourth part = X/4

Let number be 'X'> It's fifth part = X/5> Fourth part = X/4X/5 + 5 = X/4 - 5

Let number be 'X'> It's fifth part = X/5> Fourth part = X/4X/5 + 5 = X/4 - 5> (X + 25) / 5 = (X -20) / 4

Let number be 'X'> It's fifth part = X/5> Fourth part = X/4X/5 + 5 = X/4 - 5> (X + 25) / 5 = (X -20) / 4> 4(X + 25) = 5(X - 20)

Let number be 'X'> It's fifth part = X/5> Fourth part = X/4X/5 + 5 = X/4 - 5> (X + 25) / 5 = (X -20) / 4> 4(X + 25) = 5(X - 20)> 4X + 100 = 5X - 100

Let number be 'X'> It's fifth part = X/5> Fourth part = X/4X/5 + 5 = X/4 - 5> (X + 25) / 5 = (X -20) / 4> 4(X + 25) = 5(X - 20)> 4X + 100 = 5X - 100> 5X - 4X = 200

> Hence, X = 200

Hope it helps you friend

Answer 2

Answer:

200 is answer dear friend