Question

find the number whose fifth part incresed by 5 is equal to its fourth part is dimnished by 5

Answer 1

Let the number be a

According to question

a/5 + 5 = a/4 - 5

=> 5 + 5 = a/4 - a/5

=> 10 = ( 5a - 4a) / 20

=> 10 = a/20

=> a = 200

Required number = 200

Answer 2

let number be x
fifth part =x/5
increased by 5 = x/5 +5
fourth part =x/4
diminished by 5 = x/4-5
x/5 +5 = x/4 -5
x/4 - x/5 =10
take lcm
5x-4x/20 =10
x/20 =10
x=20*10 =200 is the answer