Question

Find the number whose
number whose 13% is 65.
Find the number whose 6-% is 2.​

Answer 1

Answer:

Let the required number be x.

Atq,

$\: \: \: \: \: \: \: 13\% \: of \: x = 65$

$= > \frac{13}{100} \times x = 65$

$= > \frac{13x}{100} = 65$

$= > 13x = 100 \times 65$

$= > x = \frac{100 \times 65}{13}$

$= > x = 500$

Hence, the required number is 500.

Let the required number be x.

Atq,

$\: \: \: \: \: \: \: \: 6\% \: of \: x = 2$

$= > \frac{6}{100} \times x = 2$

$= > \frac{3x}{50} = 2$

$= > 3x = 50 \times 2$

$= > x = \frac{50 \times 2}{3}$

$= > x = \frac{100}{3}$

$= > x = 33.33$