Find the number whose one-third multiplied by its one-sixth becomes 162
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let required number be x
one third of x = x/3
one sixth of x = x/6
given (x/3) × (x/6) = 162
⇒ x² = 162 × 3 × 6
⇒ x² = 9×9×2×2×3×3
⇒ x = 9 × 2 × 3 = 54
hence required number is 54
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Answer:
let required number be x
one third of x = x/3
one sixth of x = x/6
given (x/3) × (x/6) = 162
⇒ x² = 162 × 3 × 6
⇒ x² = 9×9×2×2×3×3
⇒ x = 9 × 2 × 3 = 54
hence required number is 54
Step-by-step explanation:
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