Question

find the number whose soms is
16 and the product is 63.​

Answer 1

Step-by-step explanation:

Let numbers are x and y

x+y=16........(1)

xy=63

x=63y.........(2)

Put the value of x in (1)

63/y+y=16

Multiply by y both sides

63+y^2=16y

Rearrage above equation

y^2-16y+63=0

y^2-9y-7y+63=0

y(y-9)-7(y-9)=0

(y-7)(y-9)=0

y-7=0 or y-9=o

y=7 or y=9

Put the values of y in (1)

x=7

x+y=16

x+7=16

x=16-7

x=9

x+9=16

x=16-9

x=7

if one number is 7 other will be 9 or one is 9 other will be 7.

So numbers are 7 and 9

Answer 2

$\huge\sf\underline{\underline{\blue{given}}}$

$\textit{sum of two numbers = 16}$

$\textit{product of two number s =63}$,

$\huge\sf\underline{\underline{\green{solution}}}$

$\textit{❥let one number be 'x'and second be 'y'}$

$\textit{❥than according to first condition.}$

➠ $\textit{x + y = 16}$___( i)

$\textit{❥now according to second condition.}$,

➠$\textit{x × y = 63}$____(ii)

$\textit{❥according to equation first}$

➠ $\textit{x + y = 16}$

➠ $\textit{x = 16- y }$____(¡¡¡)

$\textit{❥putting value of"x" in equation second}</p><p>$

➠ $\textit{x × y = 63}$

➠ $\textit{(16-y )y = 63}$

➠$\textit{16y - y2 = 63}$

➠$\textit{y2 -16y + 63 = 0}$

➠ $\textit{y2 - 9y-7y + 63 = 0}$

➠ $\textit{y ( y - 9) - 7( y - 9) = 0}$

➠$\textit{(y-7) (y - 9)= 0}$

➠ $\textit{y = 7 or 9}$

$\huge\sf\underline{\underline{\red{AnsWeR}}}$,

✰$\textit{if y = 7 then 'x' = 16-7 = 9}$

✰$\textit{if y = 9 then 'x' = 16-9 = 7}$