Question

find the number whose sum is 13 and product is -420​

Answer 1

Answer:

hope u like the answer and please like

let one no. be x

therefore, other no.be 13-x

now A/Q

(13-x)x=-420

13-x^2=-420

find the rest by yoursef

Answer 2

Answer:

number is 67 or 76

Step-by-step explanation:

let the numbers = x and y

x + y = 13 -----(1)

xy = -42 --------(2)

from eq 1

x = y - 13

put x in eq 2

(y - 13)y = -42

y² - 13y + 42 = 0

y² -(7+6)y + 42 = 0

y² - 7y - 6y + 42 = 0

y(y - 7).-6(y - 7) = 0

(y - 6)(y - 7) = 0

y - 6 = 0 , y - 7 = 0

y = 6 , y = 7

if y = 6

then, x = 13 - y = 13 - 6 = 7

if y = 7

then , x = 13 - y = 13 - 7 = 6

given number is 67 or 76

may be it's -42 not -420