Math, asked by son3, 1 year ago

find the number whose tenth part increased by 10 is equal to its eighth part diminished by 10.

Answers

Answered by kumarishiwangi

let the number be x.
then,
x/10+10 = x/8-10
x+100/10=x-80/8
8(x+100)=10(x-80) .............(by cross multiplication)
8x+800=10x-800
8x-10x= -800-800
-2x= -1600
2x= 1600
x= 1600/2
x=800

kumarishiwangi: mark ths ans brailiest

TheRuhanikaDhawan: nice

kumarishiwangi: thank u .. ;)

Anonymous: nice answer

kumarishiwangi: thanks

son3: thanks

Anonymous: thank you very much

Anonymous: hi son3

Answered by dikshaverma4you

Let the no. be x...... ATQ.....x/10+10=x/8-10..............x/10-x/8=-10-10...............4x-5x/40= -20.......-1x/40=-20.......x=-20×40/-1( - sign gets cancelled).............x=800....

Anonymous: i hate u

dikshaverma4you: Hey y u reported my ans. Rocking boy ??. What have I done

Anonymous: i didn't

dikshaverma4you: See the log..... Its written there that u have reported my ans.

dikshaverma4you: Check it

kumarishiwangi: plz..buddies cool down we are not allowed to talk heree....otherise mod.will delete the answer

dikshaverma4you: Ok.ok.... I only want to know that y he reported my ans.

kumarishiwangi: i don't know that

Anonymous: ok bye for all except kumarishiwangi

dikshaverma4you: Hmm. Bye

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