Find the number whose tenth part increased by 10 is equal to its eighth part diminished by 10
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let the no. x
ATQ,
x/10+10=x/8-10
(x+100)/10=(x-80)/8
8(x+100)=10(x-80)
8x+800=10x-800
-2x=-1600
x=800
it is the answer
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ATQ,
x/10+10=x/8-10
(x+100)/10=(x-80)/8
8(x+100)=10(x-80)
8x+800=10x-800
-2x=-1600
x=800
it is the answer
plz follow me
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