find the numberof solid sphereeach radius 0.25cm which may be formed from a solid sphere of radius 4 cm
abhirocks733:
ans me i didn't get the ans
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radius of small sphere (r) = 0.25cm
radius of large sphere (R) = 4 cm
let the total number of small sphere formed = n

radius of large sphere (R) = 4 cm
let the total number of small sphere formed = n
Answered by
0
volume of big sphere=4/3*pi*R*R*R
4/3*22/7*64
no.of spheres*volume of 1 small sphere=volume of big sphere
let the no.of sphere be y
y(4/3*22/7*0.25*0.25*0.25)=4/3*22/7*64
4/3 and 22/7 on both sides get cancelled
y=64/0.015625
y=4096
therefore, no.of spheres are 4096
4/3*22/7*64
no.of spheres*volume of 1 small sphere=volume of big sphere
let the no.of sphere be y
y(4/3*22/7*0.25*0.25*0.25)=4/3*22/7*64
4/3 and 22/7 on both sides get cancelled
y=64/0.015625
y=4096
therefore, no.of spheres are 4096
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