Math, asked by waghmoderupali212, 1 month ago

find the numbers divisible by 3 from 12,23,36,48,52,57,47,35​

Answers

Answered by affumunnagunda
37

Answer:

12,36,48,57

hope it's helpful

Answered by payalchatterje
0

Answer:

The numbers divisible by 3 from 12,23,36,48,52,57,47,35 are 12,36,48,52,57.

Step-by-step explanation:

Any number is called divisible by 3 if the sum of all digits of that number is divisible by 3.

For example 1223 is a number.

Sum of all digits of 1223 is (1 + 2 + 2 + 3) = 8

but 8 is not divisible by 3.

So,1223 is not divisible by 8.

Here given numbers are 12,23,36,48,52,57,47,35.

Sum of all digits of 12 is (1 + 2) = 3

3 is divisible by 3.

So,12 is also divisible by 3.

Sum of all digits of 23 is (2 + 3) = 5

But 5 is not divisible by 3.

So,23 is not divisible by 3.

Sum of all digits of 36 is (3 + 6) = 9

and 9 is divisible by 3.

So,36 is divisible by 3.

Sum of all digits of 48 is (4 + 8) = 12

and 12 is divisible by 3.

So,48 is divisible by 3.

Similarly we can check 52,57,47 and 35.

As a result we get 52 and 57 are divisible by 3.

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