Question

find the numbers ,if the sum of three consecutive numbers is 48.​

Answer 1

Step-by-step explanation:

so we have: n + n+1 + n+2 = 48. so our numbers should be 15, 16, and 17.

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Answer 2

find the numbers ,if the sum of three consecutive numbers is 48.

$let \: the \: first \: no. \: be \: x \\ second \: no. \: be \: x + 1 \\ third \: no. \: be \: x + 2 \\ \\ we \: know \: that \: the \: sum \: of \: three \\ integer \: is \: 48 \\ \\ therefore \\ x + x + 1 + x + 2 = 48 \\ 3x + 3 = 48 \\ 3x = 48 - 3 \\ 3x = 45 \\ x = \frac{45}{3} \\ x = 15 \\ \\ so \: the \: three \: integers \: are \: \\ first \: integer = 15 \\ second \: integer \: = 16 \\ third \: integer = 17 \\ \\ if \: we \: will \: add \: them \: together \: we \: will \: get \\ 15 + 16 + 17 = 48$

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