find the numbers if three numbers are in ratio 2: 6: 7 & their product is 84000.
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Answer:
let first number is = 2x
Second number is = 6x
third number is = 7x
their product= 84, 000
(2x) (6x) (7x) = 84, 000
84x^3 = 84, 000
x^3 = 84, 000 / 84
x^3 = 1, 000
X = 10
first number = 2× 10
= 20
second number = 6 × 10
= 60
third number = 7 × 10
= 70
verification
= 20 × 60 × 70
= 84, 000
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