Find the numbers in gp whose sum is 38 and product is 1728.
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61
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Although a right angle is 90 degrees, it can't be called a complementary because it doesn't appear in pairs. It is just a complete one angle. Three angles or more angles whose sum is equal to 90 degrees cannot also be called complementary angles.
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Let a/r, a, and ar be the three numbers in GP.
Sum, a/r + a + ar = 38 …(i)
Product, (a/r)a(ar) = 1728
a3 = 1728
Taking cube root
a = 12
Substitute a in (i)
(12/r) + 12 + 12r = 38
(12/r) + 12r = 26
((1/r) + r) = 26/12
(r2 + 1)/ r = 13/6
6r2-13r+6 = 0
Solving using the quadratic formula, we get
r = ⅔ or 3/2
The numbers will be 18, 12, 8 or 18, 12, 8.
Please mark as the brainliest answer.
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