Question

.Find the numbers of diagonal in regular 12 sided polygon?​

Answer 1

Answer:

The number of diagonals (we'll label diagonals as "d") that can be drawn in a polygon of "n" sides is given by the formula:  

d =  

n(n-3)

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2  

Ok, so that fraction doesn't look very good. I'm trying to say that the formula for diagnoals in a polygon is n(n-3) over 2.  

Let's use your 12 sided figure as our example:  

12(12-3)/2 <---- this is a fraction of 12(12-3) over 2  

12(9)/2 is the same as 12 x 9 over 2  

108/2 is the same as 108 over 2  

108/ 2 = 54  

Soooooooo we can draw 54 diagonals in a 12 sided figure

Step-by-step explanation:

OR Ok, so that fraction doesn't look very good. I'm trying to say that the formula for diagnoals in a polygon is n(n-3) over 2. Soooooooo we can draw 54 diagonals in a 12 sided figure. cool.

Answer 2

We know that,

• the number of distinct diagonals that can be drawn in a dodecagon from all its vertices. We will use the formula to get the number of diagonals of the polygon having n sides, where n is the number of sides = 12 (given).

• $\sf \: \dfrac{1}{2} \times n \times (n - 3)$

Substituting the value of n = 12, we will get,

• $\sf \: \dfrac{1}{2} \times 12 \div (12 - 3)$

Now Simplify,

$\sf \: 6 \times (9)$

Removing the brackets, we will get,

$\text6 \times 9 = 54$

∴ Hence, there are 54 diagonals in a polygon having 12 sides.

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