Question

Find the numbers of integers between 30 and 300 which are divisible by 8

Answer 1

AP: 32,40,48.................296

a=32

d=8

an=296 (divide 300 by 8 and subtract the the remainder with 300)

an=a+(n-1)d

296=32+(n-1)*8

296-32= 8n-8

264+8=8n

272/8=n

n = 34

Answer 2

Answer:

34

Step-by-step explanation:

AP: 32,40,48.................296

a=32

d=8

an=296 (divide 300 by 8 and subtract the the remainder with 300)

an=a+(n-1)d

296=32+(n-1)*8

296-32= 8n-8

264+8=8n

272/8=n

n = 34

• therefore there are 34 integers between 30 &300 which are divisible by 8