find the numbers of terms of an Ap in which the first term is -2, the common difference is -3 and the last term is -17
Answers
Answered by
2
Answer:
Given, first term (a )= 10, Last term (l) = 361, common difference(d) = 9, Assume number of terms be n.
l =a + (n −1)d
361 = 10 + (n - 1)9
361 - 10 = 9(n -1)
9(n-1) = 351
n - 1 = 39
n = 40
Similar questions