Question

Find the numbers such that twice the greater exceeds 3 times the smaller by 10 and one fifths ofvthe greater is lessthan one rhird of the smallesr by20

Answer 1

Answer:

850,-570

Step-by-step explanation:

let X be greater number,and y be lesser number

(2*X)=(3*y)+10;

(X/5)-20=(y/3);

eqn 2 can be written as 3x-5y=300;

therefore by solving,6x-9y=30;

6x-10y=600;

solving above eqns,we get ,y=-570;X=850