Math, asked by riddhishah2007, 10 months ago

find the numbers whose products is a one digit number and the sum is two digit number 5417,9132,8621,3751,6193,1476,2735,6528

Answers

Answered by lakshkon
0

Answer:

1 & 9

Step-by-step explanation:

First I have to assume that we’re constrained to integers, a reasonable assumption since you’re talking about “1 digit numbers” and “2 digit numbers.” (How many digits does 0.5 have? Let’s not go there.)

This is the kind of problem you solve by inspection. There aren’t many combinations of integers that, when multiplied, give a one digit answer. Let’s write them all out.

1*1, 1*2, 1*3, 1*4, 1*5, 1*6, 1*7, 1*8, 1*9

2*2, 2*3, 2*4

3*3

And that’s all there is. Looking at the list it’s clear the only one that adds up to a two digit number is 1 and 9..

Another explanation :

We need to find the two numbers whose product is a one digit number and the sum is a two digit number.

The approach to the question is to extract first and last digit of the number and then add and multiply the digits separately. Next, adding the sum and product of the digits of the two-digit number and comparing it to the original number. Thus, ff the numbers are same, then it is a special two-digit number, else it is not.

Thus, the possible two numbers are 1 and 9

The product of 1 and 9 = 1 × 9 = 9  and

The sum of 1 and 9 = 1 + 9 = 10

Therefore, the numbers 1 and 9 are the two numbers.

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Answered by sravanthimedam999
0

Answer:

1 ᗩᘉᕲ 9

ᗩᖇᘿ ᖶᕼᘿ

ᗩᘉSᘺᘿᖇS

for your quesion

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