find the numbersssss
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given sum of two numbers is 9
if we think one number as " x "
then the other number will be 9 - x
And given sum of their reciprocals is 12
( 9-x ) + ( x ) / ( x ) * ( 9 - x ) = 12
9 / 9x - x sq = 12
( On cross multiplication )
9 = 12 ( 9x - x sq )
9 = 108 x - 12x sq
( On dividing the whole equation with " 3 " )
3 = 36x - 4x sq
4x sq - 36x + 3 = 0
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let x and x+1are the two numbers
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