find the numbet terms of A.P.54,51,48.....so the that their sum is 513 soln
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here
a=54,
d=-3,
Sn=513,
n=?,
Sn =n/2[2a+(n-1)d],
513=n/2[2×54+(n-1)×(-3)],
513=n/2[108-3(n-1)],
513=n/2[108-3n+3],
1026=n[111-3n],
1026=111n-3n²,
then
3n²-111n+1026=0,
then
n²-37n+342=0,
n²-(19+18)n+342=0,
n²-19n-18n+342=0,
n(n-19)-18(n-19)=0,
(n-19)(n-18)=0,
if
n-19=0,
then
n=19,
if
n-18=0,
then
n=18
a=54,
d=-3,
Sn=513,
n=?,
Sn =n/2[2a+(n-1)d],
513=n/2[2×54+(n-1)×(-3)],
513=n/2[108-3(n-1)],
513=n/2[108-3n+3],
1026=n[111-3n],
1026=111n-3n²,
then
3n²-111n+1026=0,
then
n²-37n+342=0,
n²-(19+18)n+342=0,
n²-19n-18n+342=0,
n(n-19)-18(n-19)=0,
(n-19)(n-18)=0,
if
n-19=0,
then
n=19,
if
n-18=0,
then
n=18
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