Find the numerical difference of the root of the equation xsquare minus 7x minus 18=0
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Answered by
3
x^-7x-18=0
x^+2x-9x-18=0
x(x+2)-9(x+2)=0
(x+2)(x-9)=0
x=-2
x=9
Numerical difference is 9-(-2)
=11
x^+2x-9x-18=0
x(x+2)-9(x+2)=0
(x+2)(x-9)=0
x=-2
x=9
Numerical difference is 9-(-2)
=11
Answered by
0
x^2-7x-18=0
=> x^2-9x+2x-18=0
=> x (x-9)+2 (x-9)=0
=>(x+2)(x-9)=0
=> x=-2,9
hence roots of equation are -2 and 9
so difference of root =-2-9= -11
or =9-(-2)=11
hence difference of roots are -11 and 11
=> x^2-9x+2x-18=0
=> x (x-9)+2 (x-9)=0
=>(x+2)(x-9)=0
=> x=-2,9
hence roots of equation are -2 and 9
so difference of root =-2-9= -11
or =9-(-2)=11
hence difference of roots are -11 and 11
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