Question

find the numerical value .​

Answer 1

Answer:

(1+sinA)/(1-sinA) =9

1+sinA=9-9sinA

10sinA=8

sinA=4/5

cosA=√(1-sin²A) =√(1-16/25(=3/5

tanA=sinA/cosA

=4/5×5/3=4/3

1+tanA/1-tanA=(1+4/3) /(1-4/3) =7/-1=-7