Math, asked by krishnamathy50, 9 months ago

Find the numerical value of the following expression, where A+B=90°. sec2A−cot2Bcsc2B−tan2A+2sin2Asec2B−3(cos2A+cos2B)

Answers

Answered by AnushkaRishivanshi

0

Answer:

sec^2A + sec^2B= sec^2Asec^2B

sec^2(90-B) + sec^2B

cosec^2B + sec^2B

1/sin^2B + 1/cos^2B

sin^2B+cos^2B/sin^2Bcos^2B

1/ssin^2Bcos^2B

sec^2Bcosec^2B

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