Math, asked by ksharna129, 13 hours ago

find the numerical value

( - x + 5) ^{2}  - 2x \: when \: x =  - 1

Answers

Answered by kadamkhushi612
0

Answer:

answer

Step-by-step explanation:

( -x + 5 )² -2

a²+2ab+b²

(-x)² + 2(-x)(5) + 5²

x + ( -10 ) + 25

x - 10 + 25 + 2x

now put x= -1

-1 ( -10 ) + 25 - 2( -1 )

11 + 25 + 3

39

so here 39 is the answer

Answered by Mysteryboy01
1

 = ( { - x + 5)}^{2}  - 2x

x =  - 1

 = ( - 1 + 5) ^{2}  - 2( - 1)

 = ( {4)}^{2}   + 2

 = 16 + 2

 = 18

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