Question

Find the odd man out 2651,2246,5324,6215

Answer 1

$Given \: numbers \: 2651, 2246, 5324,6215$

$\underline { \blue { Divisibility \:rule \:of \11:}}$

If the difference between the sum of digits in odd places and sum of the digits in even places from right to left of a number is a multiple of 11 or equal to zero, then the given number is divisible by 11.

1. 2651

• sum of digits in odd places= 1+6 = 7
• sum of digits in even places = 5+2 = 7

Now, 2651 divisible by 11.

2 . 2246.

• sum of digits in odd places = 6+2 = 8
• sum of digits in even places = 4+2 = 6

Here , Difference = 8 - 6 = 2

$\red {( 2246 \: is \:not \: divisible \:by \:11 )}$

3. 5314

• sum of digits in odd places = 4+3 = 7
• sum of digits in even places = 2+5= 7

Here, 5314 is Divisible by 11.

4. 6215

• sum of digits in odd places = 5+2 = 7
• sum of digits in even places = 1+6 = 7

Here, 6215 is Divisible by 11.

Therefore.,

$\red { Odd \:man }\\ \green { 2246 \: is \:not \: divisible \:by \:11 }$