Math, asked by saurabhkushwaha75, 10 months ago

Find the odd man out: 936, 835, 743, 741, 954, 963, 541
a) 835
b)743
c)541
d)741
Kindly tell the steps taken please

Answers

Answered by swarangiv
1

Answer:

d) 741

Step-by-step explanation:

The sum of last two digit is equal to the sum of first digit

936 = 9,3+6=9

835 = 8,3+5=8

743 = 7,4+3=7

741 = 7,4+1=5. This term doesn't show this form

954 = 9,5+4=9

963 = 9,6+3=9

541 = 5,4+1=5

Thus answer is d) 741

Answered by nandinibehera733
1

Answer:

The answer is 835 in my point of view

If we find the divisors of these numbers

And the reminders of these value then we can determine the odd one out

Reminders

936=3×4×6×12 1

835=3×5×55 2

743=7×106 1

741 =9×82 1

954=4×9×26 1

963=2×9×53 1

541 =3×180 1

So, in accordance to reminders ,835 is the answer

Similar questions