Find the odd number in the given series 14, 27, 105, 525, 4993
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odd number in the given series will be 525
14 = (13×1)+ 1
27= (13×2)+1
105 = (13×8)+1
525 = (13×40)+5
4993 = (13×384)+1
All the numbers are giving remainder 1 when they are divided by 13 except 525
14 = (13×1)+ 1
27= (13×2)+1
105 = (13×8)+1
525 = (13×40)+5
4993 = (13×384)+1
All the numbers are giving remainder 1 when they are divided by 13 except 525
Answered by
0
14 = 13× 1 +1
27 = 13× 2 + 1
105 = 13× 8 +1
4993 = 13 × 384 + 1
525 = 13× 40 + 5
SO 525
27 = 13× 2 + 1
105 = 13× 8 +1
4993 = 13 × 384 + 1
525 = 13× 40 + 5
SO 525
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