Math, asked by hm0002716, 1 year ago

Find the odd one.
1,8,27,64,125,200,343....

a.64
b. 200
c. 343
d125.


BrainlyKing5: answer is 200
BrainlyKing5: THANKS FOR MARKING AS BRAINLIEST
hm0002716: 200 is the answer
hm0002716: wc

Answers

Answered by BrainlyKing5
5
HEY MATE HERE IS UR ANSWER

ANSWER IS 200 AS

1 = (1)^3

8 = (2)^3

27 = 3^3

64 = 4 ^3

125 = 5^3

200 = wrong order

343 = 7 ^3

THEREFORE 200 IS THE ODD INSTEAD OF 200 . THERE

SHOULD BE 216 = 6 ^3

HOPE ITS HELPFUL IF YES PLEASE MARK AS BRAINLIEST !!!!!

@NIPUN
Answered by BrainlyVirat
8
Thanks for your question

The odd one in the given series 1,8,27,64,125,200,343 is 200.

Reason =>

The given sequence follows the n^3 method

That is,
 {1}^{3} = 1
2 {}^{3} = 8
.....

 {5}^{3} = 125
6 {}^{3} = 216

In the series,
It's given 200 which is wrong.

It should be replaced by 216.

Thus ,
The odd one in the given series is 200.

Thanks!!

BrainlyKing5: again i and u
BrainlyVirat: :)
BrainlyKing5: :))
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