find the odd one out
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E. becz sides 3,4,5,y. but daimond has 4sides
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c)
As all the others have total number of shapes inside them equal to their vertices .
a) Triangle has 3 vertices so there are three triangles present.
b) Square has 4 vertices so there are three squares present.
d) Pentagon has 5 vertices so there are three pentagons present.
e) Diamond has 4 vertices so there are three diamonds present.
But
c) Hexagon has 6 vertices but there are three hexagons present.
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