Math, asked by kalwanjatt, 2 months ago

find the odd one out from the option:-(100,121),(25,36),(81,90),(64,81)

Answers

Answered by RvChaudharY50
1

Given :- find the odd one out from the option:-(100,121),(25,36),(81,90),(64,81)

Answer :-

Logic :- a², (a + 1)² .

Explanation :-

→ 100 , 121 = 10² , 11²

→ 25 , 36 = 5² , 6²

→ 81 , 90 = 9² , 90 = Not a perfect square

→ 64 , 81 = 8² , 9²

therefore, we can conclude that, (81, 90) are odd one out since 90 is not a perfect square.

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Answered by amitnrw
1

Given :  (100,121),(25,36),(81,90),(64,81)

To Find : odd one out

Solution:

(100,121)

100 = 10²

121  = 11²

(25,36),

25 = 5²

36 = 6²

(81,90)

81 = 9²

90 ≠ 10²

(64,81)

64 = 8²

81 = 9²

All pairs are ( n² , (n + 1)² ) except  (81,90)

Hence    (81,90) is odd one out

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