find the odd one out from the option
CFI
RUX
LOR
SVZ
Answers
Answer:
suz
Step-by-step explanation:
suz
+3 +3
C → F → I
+3 +3
U → X → A
+3 +3
R → U → X
+3 +3
L → O → R
But,
+3 +4
S → V → Z
Therefore, ‘SVZ’ does not belong to the group.
Given :- Find the odd one out from the option :-
A) CFI
B) RUX
C) LOR
D) SVZ
Solution :-
we know that, 1A, 2B, 3C, 4D, 5E, 6F, 7G, 8H, 9I, 10J, 11K, 12L, 13M, 14N, 15O, 16P, 17Q, 18R, 19S, 20T, 21 U, 22V, 23W, 24X, 25Y and 26Z.
so, checking positions of all alphabets of given options we get,
A) CFI
→ C = 3
→ F = 6
→ I = 9
- All alphabets are multiple of 3 or difference between them is 3 .
B) RUX
→ R = 18
→ U = 21
→ X = 24
- All alphabets are multiple of 3 or difference between them is 3 .
C) LOR
→ L = 12
→ O = 15
→ R = 18
- All alphabets are multiple of 3 or difference between them is 3 .
D) SVZ
→ S = 19
→ V = 22
→ Z = 26
- All alphabets are not multiple of 3 or difference between them is not 3 .(22 - 19 = 3 but 26 - 22 = 4)
therefore, we can conclude that, (D) SVZ is odd one out from the options.
Learn more :-
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