Math, asked by jasrotiasahil784, 15 days ago

find the odd one out from the options :289,1331,2197,343​

Answers

Answered by RvChaudharY50
3

Given :- Find the odd one out from the options.(ਭਿੰਨ ਵਿਕਲਪ ਚੁਣੋ) 

A) 289

B) 1331

C) 2197

D) 343

Solution :-

checking all options one by one we get,

A) 289

→ 289 = 17 * 17 = 17²

B) 1331

→ 1331 = 11 * 11 * 11 = 11³

C) 2197

→ 2197 = 13 * 13 * 13 = 13³

D) 343

→ 343 = 7 * 7 * 7 = 7³ .

as we can see that, B , C and D are cubes of prime numbers but A is square of a prime number .

Therefore, we can conclude that (A) 289 is odd one out from the given option .

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Answered by amitnrw
0

Given :   289 , 1331 , 2197 , 343

To Find : odd one out

Solution:

289 = 17²

1331 = 11³

2197 = 13³

343  = 7³

Except 289 all other terms are perfect cube

Hence 289 is odd one out

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