Question

Find the % of S in BaSO4 ig 2.5g of BaSO4 is produced from the organic compos having a mass of 4g​

Answer 1

Answer:

The number of moles of MgSO

4

n=

molar mass

mass

=

120g/mol

4g

=0.03333 mol.

Mass of water is 100 g or

1000g/kg

100g

=0.1 kg

The molality of the solution is m=

mass of water in kg

moles of MgSO

4

m=

0.1kg

0.03333mol

=0.3333m

MgSO

4

→Mg

2+

+SO

4

2−

The vant Hoff factor i=2 (as dissociation of 1 molecule of magnesium sulphate gives 2 ions)

The elevation in the boiling point ΔT

b

=iK

b

m=2×0.52×0.3333=0.3466K

The boiling point of pure water is 373.15 K.

The boiling point of solution will be 373.15+0.3466=373.4966K≃373.5K.

Explanation:

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