Question

find the of the circle having (2,3) and (4,0) as the end point of a diameter​

Answer 1

Correct Question:-

Find the radius of the circle having (2,3) and (4,0) as diameter.

Answer:-

Co-ordinates of diameter

• (2,3)
• (4,0)

Find length of diameter

• formula is

$\boxed{\sf \sqrt{(x_1-x_2)^2+(y_1-y_2)^2}}$

$\\ \rm\longmapsto \sqrt{(2-4)^2+(3-0)^2}$

$\\ \rm\longmapsto \sqrt{(-2)^2+(3)^2}$

$\\ \rm\longmapsto \sqrt{4+9}$

$\\ \rm\longmapsto \sqrt{13}$

$\\ \rm\longmapsto 3.2units$

We know that

$\boxed{\sf Radius=\dfrac{Diameter}{2}}$

$\\ \rm\longmapsto Radius=\dfrac{3.2}{2}$

$\\ \rm\longmapsto Radius=1.6units$