Math, asked by vanshgupta66, 11 months ago

find the of unknown angle in each case​

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Answered by mlpian30
1

Answer:

In triangle PQR,

RPQ+RQP+QRP = 180°

60°+75°+x+20°=180°

x=180°-155°

x= 25°

So,RQP=25°+20°

RQP=55°

and SRP = 25°

Answered by yash50933
2

Here is your answer

In Triangle PQR

All angles = 180

Then 60+75+x+20=180

= x= 180-155

x= 25

Remaining angle =25

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