Question

find the on the x-axis , each of which is a distance of 10unit from the point A(11,-8)​

Answer 1

Answer:

The points are (5,0) and (17,0)

Step-by-step explanation:

At the x axis, the y coordinate is zero. Hence, any point on the x axis has a coordinate (x,0).

Now, this point is at a distance of 10 units from the point a(11,-8)

The distance formula is given by

d = √(x₂ - x₁)² ₋ (y₂ - y₁)²

10 = √ (11 - x)² + ( - 8 - 0)²

Squaring both sides, we get

100 = ( 11 - x )² + ( - 8 - 0)²

100 = 121 + x² - 22x + 64

x² - 22x + 85 = 0

x² - 17x - 5x + 85 = 0

x ( x - 17 ) - 5 ( x - 17) = 0

(x - 17) (x-5) = 0

x = 5 , 17

Therefore, the points are (5,0) and (17,0)